What is the output PEP from a transmitter if an oscilloscope measures 500 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?

Why

To find the power, first turn the 500 volts peak-to-peak into a peak voltage of 250 volts, then convert that to a root mean square value of about 177 volts, which represents the steady heating effect of the signal. The full explanation — and one for every question — is in Pro.

Practise this section

Measurements is section A-003 of the Advanced exam: Measurements: meters, oscilloscopes, counters, signal generators, and what a reading actually tells you.

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