What is the output PEP from a transmitter, if an oscilloscope measures 800 volts peak-to-peak across a 50 ohm dummy load connected to the transmitter output?

Why

To find the output power, first turn the 800 volts peak-to-peak reading into a peak value by dividing by two, giving 400 volts. The full explanation — and one for every question — is in Pro.

Practise this section

Measurements is section A-003 of the Advanced exam: Measurements: meters, oscilloscopes, counters, signal generators, and what a reading actually tells you.

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